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1.6 crop factor and f stop question

gtcgtc Registered Users Posts: 916 Major grins
edited October 7, 2005 in Technique
i am still waiting on my m42 screwmount to eos adapter so that i can mount my super- multi -coated takumar f4/200 on my canon 20d.i have also ordered a smc 300mm so that i can go birding.

in the meantime a question-with the 1.6 crop factor my sensor will be looking at an image circle within the centre of the lens and crop out the edges,thus removing any problems with edge softness etc.

i am probably off track but have been ruminating on this one for awhile.

as f is calculated on the light passing through the whole lens,including the edges which are a little 'thicker', would i be right in assuming that a cropped image circle would be brighter/faster than if using a full frame sensor or film camera?

if so how would i determine the level of improvement to the glass speed?

if not,why not?

looking forward to having this question settled.

greg
Latitude: 37° 52'South
Longitude: 145° 08'East

Canon 20d,EFS-60mm Macro,Canon 85mm/1.8. Pentax Spotmatic SP,Pentax Super Takumars 50/1.4 &135/3.5,Pentax Super-Multi-Coated Takumars 200/4 ,300/4,400/5.6,Sigma 600/8.

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    Shay StephensShay Stephens Registered Users Posts: 3,165 Major grins
    edited October 6, 2005
    The answer is a simple no. f/4 is f/4 is f/4.

    Why you ask? The answer to that lies in how f/numbers are calculated in the first place.

    f/4 is a ratio of the diameter of the aperture in the lens and the focal length of the lens.

    It has nothing to do with how the image circle is used to record the final image.

    f/4 simply means that the aperture of the lens is 1/4 of the lens focal length (if we were using f/8 that would 1/8). So if you have a 200mm lens, the aperture opening is going to be 50mm which is going to let in a known amount of light and create an image circle with a standard brightness. How the camera cuts into that circle to record the image has no bearing on the resulting brightness of the image circle.

    So fire away, content with the knowledge that you don't have to deal with any more math conversions than is necessary :-)

    More info on f/stops:
    http://en.wikipedia.org/wiki/F-number
    Creator of Dgrin's "Last Photographer Standing" contest
    "Failure is feedback. And feedback is the breakfast of champions." - fortune cookie
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    gtcgtc Registered Users Posts: 916 Major grins
    edited October 6, 2005
    so..?
    thanks shay,

    so the image circle brightness is the same level of brightness across the image circle -eg the edges are transmitting just as much light/brightness as is in the centre of the lens?

    if so, this clears things up for me and i can think about something else in idle moments...

    thanks

    greg

    The answer is a simple no. f/4 is f/4 is f/4.

    Why you ask? The answer to that lies in how f/numbers are calculated in the first place.

    f/4 is a ratio of the diameter of the aperture in the lens and the focal length of the lens.

    It has nothing to do with how the image circle is used to record the final image.

    f/4 simply means that the aperture of the lens is 1/4 of the lens focal length (if we were using f/8 that would 1/8). So if you have a 200mm lens, the aperture opening is going to be 50mm which is going to let in a known amount of light and create an image circle with a standard brightness. How the camera cuts into that circle to record the image has no bearing on the resulting brightness of the image circle.

    So fire away, content with the knowledge that you don't have to deal with any more math conversions than is necessary :-)

    More info on f/stops:
    http://en.wikipedia.org/wiki/F-number
    Latitude: 37° 52'South
    Longitude: 145° 08'East

    Canon 20d,EFS-60mm Macro,Canon 85mm/1.8. Pentax Spotmatic SP,Pentax Super Takumars 50/1.4 &135/3.5,Pentax Super-Multi-Coated Takumars 200/4 ,300/4,400/5.6,Sigma 600/8.
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    Shay StephensShay Stephens Registered Users Posts: 3,165 Major grins
    edited October 6, 2005
    gtc wrote:
    thanks shay,

    so the image circle brightness is the same level of brightness across the image circle -eg the edges are transmitting just as much light/brightness as is in the centre of the lens?
    Nope. the light intensity typically drops towards the edges depending on the lens. Wide angle tends to vignette towards the edges more than telephoto.
    Creator of Dgrin's "Last Photographer Standing" contest
    "Failure is feedback. And feedback is the breakfast of champions." - fortune cookie
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    gtcgtc Registered Users Posts: 916 Major grins
    edited October 7, 2005
    doesent that mean..
    Nope. the light intensity typically drops towards the edges depending on the lens. Wide angle tends to vignette towards the edges more than telephoto.
    thanks shay,

    sorry to be a pain but you either seem to be agreeing with me or i have missed the point

    -so therefore the light measured at full aperture across the whole lens/image circle for a full frame sensor/35mm film would be less bright than the light measured across the reduced image circle of a 1.6 crop sensor?

    doesen't this mean that the cropped image circle will be brighter than the larger image circle due to the removal of the duller edges by cropping,and therefore resulting in greater brightness and therefore a faster lens?

    greg
    Latitude: 37° 52'South
    Longitude: 145° 08'East

    Canon 20d,EFS-60mm Macro,Canon 85mm/1.8. Pentax Spotmatic SP,Pentax Super Takumars 50/1.4 &135/3.5,Pentax Super-Multi-Coated Takumars 200/4 ,300/4,400/5.6,Sigma 600/8.
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    DavidTODavidTO Registered Users, Retired Mod Posts: 19,160 Major grins
    edited October 7, 2005
    Dang Shay. You are a veritable fount of information. And most of it's good!

    Thanks for explaining that one. I never knew how simple the concept was.
    The answer is a simple no. f/4 is f/4 is f/4.

    Why you ask? The answer to that lies in how f/numbers are calculated in the first place.

    f/4 is a ratio of the diameter of the aperture in the lens and the focal length of the lens.

    It has nothing to do with how the image circle is used to record the final image.

    f/4 simply means that the aperture of the lens is 1/4 of the lens focal length (if we were using f/8 that would 1/8). So if you have a 200mm lens, the aperture opening is going to be 50mm which is going to let in a known amount of light and create an image circle with a standard brightness. How the camera cuts into that circle to record the image has no bearing on the resulting brightness of the image circle.

    So fire away, content with the knowledge that you don't have to deal with any more math conversions than is necessary :-)

    More info on f/stops:
    http://en.wikipedia.org/wiki/F-number
    Moderator Emeritus
    Dgrin FAQ | Me | Workshops
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    Shay StephensShay Stephens Registered Users Posts: 3,165 Major grins
    edited October 7, 2005
    Perhaps I don't understand the point you are getting at
    If you have a focal length of 17mm, the edges would be brighter with a 1.6x crop, however, if you zoomed the lens on a full frame camera to 26mm you would have the same brightness at the edges since the image circle would now cover the same area as the 1.6x crop camera.

    But the overall image would be just as bright on both cameras, and the exposure needed to properly render the scene would be the same with both cameras regardless of the vignetting at the edges.

    Vignetting is an optical defect (for good or ill) and if you base your exposure on having properly exposed corners, you will overexpose the overall frame. A cropped frame does not get any brighter, it just hides more of the vignetting at the edges.

    Remember, f/4 is f/4 is f/4 ;-)

    gtc wrote:
    thanks shay,

    sorry to be a pain but you either seem to be agreeing with me or i have missed the point

    -so therefore the light measured at full aperture across the whole lens/image circle for a full frame sensor/35mm film would be less bright than the light measured across the reduced image circle of a 1.6 crop sensor?

    doesen't this mean that the cropped image circle will be brighter than the larger image circle due to the removal of the duller edges by cropping,and therefore resulting in greater brightness and therefore a faster lens?

    greg
    Creator of Dgrin's "Last Photographer Standing" contest
    "Failure is feedback. And feedback is the breakfast of champions." - fortune cookie
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