And bought my stuff from here in Germany, I am sure it can be sourced elsewhere but this was much cheaper than the high street
I think I bought This because of the wider degree of luminosity but I think the brighter one at 22000mcd is brobably better. The description thread shows the diagram here using 62ohms 1/8th watt resistors so I did and it turned out to be 6volts total.
Oh and I bought little clip cups to hold the leds I glued them in place.
Good luck
Stan
Ok here is your challenge.
The LED's you substituted are 3.6 V, 20 mA
That is what they need to ignite.
With a 6V battery that would need (6-3.6= 2.4 V to get a 2.4 volt drop at 20 mA you need a U=IXR 2.4=.020AXR R=120 ohms) or with a 9V battery you would need (9-3.6=5.4V 5.4 drop at 20 mA => 270 Ohm).
The error snuck in your replacement, most LED's are 5 V and 30 mA, in which
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http://www.pinhole.cz/en/pinholecameras/dirkon_01.html
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The LED's you substituted are 3.6 V, 20 mA
That is what they need to ignite.
With a 6V battery that would need (6-3.6= 2.4 V to get a 2.4 volt drop at 20 mA you need a U=IXR 2.4=.020AXR R=120 ohms) or with a 9V battery you would need (9-3.6=5.4V 5.4 drop at 20 mA => 270 Ohm).
The error snuck in your replacement, most LED's are 5 V and 30 mA, in which
6V battery => 33 ohms
9V battery => 133 ohms
or for lower intensity LED's 20 mA
6V battery => 50 ohms
9V battery => 200 ohms
For more information on Ohms law
http://www.google.com/search?q=ohms+law
FWIW, YMMV,
XO
Mark Twain
Some times I get lucky and when that happens I show the results here: http://www.xo-studios.com
thanks for the help.
Tim
Speak with sweet words, for you never know when you may have to eat them....